Question #162787

A 500g uniform sphere of 7cm radiud ppins at 30 rev/sec on an axis through its center

Find it's kinetic energy rotational


1
Expert's answer
2021-02-11T08:53:56-0500
KEr=12Iω2,KE_r=\dfrac{1}{2}I\omega^2,KEr=1225mr2ω2=15mr2ω2.KE_r=\dfrac{1}{2}\dfrac{2}{5}mr^2\omega^2=\dfrac{1}{5}mr^2\omega^2.KEr=150.5 kg(0.07 m)2(30 revs2π rad)2=17.41 J.KE_r=\dfrac{1}{5}\cdot0.5\ kg\cdot(0.07\ m)^2\cdot(30\ \dfrac{rev}{s}\cdot2\pi\ rad)^2=17.41\ J.

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