Question #161933

A 9900 N small car is moved by a 650N force. If the car starts from rest, then how fast is it traveling after 111 m? 


Expert's answer

a) Let's first find the mass of the car:


m=Wg=9900 N9.8 ms2=1010 kg.m=\dfrac{W}{g}=\dfrac{9900\ N}{9.8\ \dfrac{m}{s^2}}=1010\ kg.

Then, we can find the acceleration of the car:


a=Fm=650 N1010 kg=0.64 ms2.a=\dfrac{F}{m}=\dfrac{650\ N}{1010\ kg}=0.64\ \dfrac{m}{s^2}.

Finally, we can find the velocity of the car after it traveled 111 meters:


vf2=vi2+2ad,v_f^2=v_i^2+2ad,vf=vi2+2ad,v_f=\sqrt{v_i^2+2ad},vf=0+20.64 ms2111 m=12 ms.v_f=\sqrt{0+2\cdot0.64\ \dfrac{m}{s^2}\cdot111\ m}=12\ \dfrac{m}{s}.
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