Answer to Question #161634 in Mechanics | Relativity for Victor

Question

An object of mass 3kg is acted upon by two horizontal forces of 6N and 3N In the opposite directions Calculate the acceleration produced by the system.

Answer 1

Let's choose the rightwards as the positive direction. Let's assume that the 6 N force directed rightward and the 3 N force directed leftward. Then, we can find the net force acting on the object:

$$F_{net}=6\ N-3\ N=3\ N.$$

Finally, from the Newton's Second Law of Motion we can find acceleration produced by the system:

$$a=\dfrac{F}{m}=\dfrac{3\ N}{3\ kg}=1.0\ \dfrac{m}{s^2}.$$