A 22 kg child is on a slide in a playground. She climbs 4.50 m to the top. Determine the velocity that the child would leave the slide if it was frictionless.
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Expert's answer
2012-10-12T08:42:33-0400
When the child is at the top of the slide, its potential energy is
P = 22[kg]*9.8[m/s²]*4.5[m] = 970.2 J.
When the child slides down, its potential energy turns into kinetic energy:
P = K = 22[kg]*(V[m/s])²/2 = 970.2 J.
Therefore,
V = √(970.2*2/22)[m/s] ≈ 9.39 [m/s].
So, the velocity of a child will be about 9.39 [m/s].
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