Question

A falling body has an initial velocity of 200 cm/seconds. How far will it drop before its velocity becomes 10000 cm/seconds.

Answer 1

From the Newtons third equation of motion

$v^2= u^2+ 2as$

where $v=$ final velocity

$u=$ initial velocity

$a=$ acceleration due to gravity( 10 m/s$^2$)

$s$ = displacement

$100^2= 2^2+ 2 \times 9.8 \times s$

$10000 - 4= 19.6s$

$s= \frac{9996}{19.6} = 510 m$