Answer to Question #160030 in Mechanics | Relativity for Hilwa musa

Question #160030

A velocity of magnitude 40m per sec is directed at an angle of 40degree east of north.draw a vector to represent this velocity


1
Expert's answer
2021-01-31T03:41:00-0500

Let's first calculate the horizontal and vertical component's of the velocity vector:


vx=vcosθ=40 mscos40=30.6 ms,v_x=vcos\theta=40\ \dfrac{m}{s}\cdot cos40^{\circ}=30.6\ \dfrac{m}{s},vy=vsinθ=40 mssin40=25.7 ms.v_y=vsin\theta=40\ \dfrac{m}{s}\cdot sin40^{\circ}=25.7\ \dfrac{m}{s}.

Let's draw the vector (here one division corresponds to 5 m\s ):


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