Question

starting from rest, how long does it take moving man to reach a velocity of 5 m/sec if his acceleration is 1.75 m/sec2

Answer 1

Question 15954

For a movement with constant acceleration, $v(t) = v_0 + at$ , where $v_0$ is the initial velocity.

Hence, for our case, $v = at \Rightarrow t = \frac{v}{a} = \frac{5mls}{1.75mls^2} \approx 2.86s$ .