Question

wiley coyote runs off of a 44.1m high cliff at 16m/s . how far away from the base of the cliff does he land

Answer 1

Wiley coyote runs off of a 44.1m high cliff at 16m/s. how far away from the base of the cliff does he land

Solution:

Let:

$$H = 44.1 \, \text{m}$$ $$v = 16 \, \text{m/s}$$ $$S - ?$$

$S = v * t$, were t-time of freefalling from H

$$t = \sqrt{\frac{2H}{g}}$$ $$S = v \sqrt{\frac{2H}{g}}$$ $$S = 16 * \sqrt{\frac{2*44.1}{9.8}} = 48 \, \text{m}$$

Answer: 48 m.