Answer to Question #159189 in Mechanics | Relativity for Rina

Question

The force on bullet is given by the formula F=580-(1.8x10^5)t over the time interval t=0 to t=3x10^-3s. F is newtons. Sketch a graph F vs t for t=0 to t=3x10^-3

Answer 1

Explanations & Calculations

• Equation is given as $\small F=-(1.8\times 10^5)t+580$ which is a linear function of time & it is in the form $\small y=-mx+c$
• To plot a linear function coordinates of just 2 different points are needed.
• Therefore,

@ t=0: F=580 and @ t=$\small 3\times 10^{-3}$ : F=40

Additionally, @F=0 : t= $\small 3.2222\times 10^{-3}$

• Then graph can be plotted to be like this