In what distance will a car skid to a stop on a dry concrete road (µk = 0.7) if its brakes are locked when it is moving at 120 kph?
Answer
Distance can be written as
"s=\\frac{v^2}{2\\mu g}=\\frac{(33.3)^2}{2\\times0.7\\times9.8}=80.8m"
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