Answer to Question #158737 in Mechanics | Relativity for Onyebuchi

Question

A stone of mass 20g falls from rest from a height 8m calculate it's k.e after falling from a distance of 5m

Answer 1

From the law of conservation of energy, we have:

$$KE_{i,h=8\ m}+PE_{i,h=8\ m}=KE_{f,h=3\ m}+PE_{f,h=3\ m},$$ $$0+PE_{i,h=8\ m}=KE_{f,h=3\ m}+PE_{f,h=3\ m},$$ $$KE_{f,h=3\ m}=PE_{i,h=8\ m}-PE_{f,h=3\ m},$$ $$KE_{f,h=3\ m}=mg(h_f-h_i),$$ $$KE_{f,h=3\ m}=0.02\ kg\cdot9.8\ \dfrac{m}{s^2}\cdot(8\ m-3\ m)=0.98\ J.$$