Question #15873
Moving man starts in the negative direction with a speed of 3 m/s but is accelerating in the positive direction with acceleration of 2.75m/s^2. What is his velocity and displacement at the end of 5.00 seconds?
Expert's answer
The man's velocity at the end of 5.00 seconds is
V = -3[m/s] + 2.75[m/s²]*5.00[s] = 10.75[m/s].
After
T = 3[m/s]/2.75[m/s²] = 12/11 seconds
the man will stop. After that he begin to run in the positive direction. So, his displacement is
D = 2.75[m/s²]*(5.00[s]-12/11[s])²/2 ≈ 21 metres
in positive direction.
V = -3[m/s] + 2.75[m/s²]*5.00[s] = 10.75[m/s].
After
T = 3[m/s]/2.75[m/s²] = 12/11 seconds
the man will stop. After that he begin to run in the positive direction. So, his displacement is
D = 2.75[m/s²]*(5.00[s]-12/11[s])²/2 ≈ 21 metres
in positive direction.
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