The coefficient of friction of the box (m = 183 183 kg) and μs = 0.15 between the car platform 0.15 . Specify the shortest time for the car to reach speed 60.0 km / h without the box sliding on the car platform?
μN=mamax→\mu N=ma_{max}\toμN=mamax→
amax=μmg/m=μg=0.15⋅9.8=1.47(m/s2)a_{max}=\mu mg/m=\mu g=0.15\cdot9.8=1.47(m/s^2)amax=μmg/m=μg=0.15⋅9.8=1.47(m/s2)
v=amaxt→t=v/amax=16.67/1.47=11.34(s)v=a_{max}t\to t=v/a_{max}=16.67/1.47=11.34(s)v=amaxt→t=v/amax=16.67/1.47=11.34(s) Answer
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