A shot fired with velocity u at elevation theta hits a mark at a distance R in the same horizontal plane. If there is no air resistance, show that (u2/g)f(theta).
Maximum velocity will be u sin"\\theta".
Now, equate it to maximum potential energy.
"m*g*h=(1\/2)mu^2"
"h = (1\/2)u^2sin^2\\theta\/g" , here Sin "\\theta" part is function of "\\theta" .
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