Question

A shot fired with velocity u at elevation theta hits a mark at a distance R in the same horizontal plane. If there is no air resistance, show that (u²/g)f(theta).

Answer 1

Maximum velocity will be u sin$\theta$.

Now, equate it to maximum potential energy.

$m*g*h=(1/2)mu^2$

$h = (1/2)u^2sin^2\theta/g$ , here Sin $\theta$ part is function of $\theta$ .