Question #15852

This question is simple kinematics. If the initial velocity is 22 m/s and the ball is headed upwards we are trying to figure out time correct? so We know that when a ball reaches its maximum height it is at a velocity of 0. In this case there is no acceleration listed, so we can assume that the acting force is gravity. (- 9.81 m/s squared.) Now that we have an initial velocity, a final velocity, and an acceleration we can solve for t using the formula. v final - v initial divided by acceleration = T

Expert's answer

We know that the velocity of the ball at the highest point will be equal to the zero. So, we can use the formula (actually gg is negative):


Vend=Vstart+gtt=VendVstartg=022(9.81)=2.243 s.V_{end} = V_{start} + g \cdot t \Rightarrow t = \frac{V_{end} - V_{start}}{g} = \frac{0 - 22}{(-9.81)} = 2.243 \text{ s}.


Answer: 2.243 s.

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