Question

The drive had to stop suddenly. The cars shock absorber had an elastic potential energy of 258J The spring constant of the shock absorber is 45300 N/m. Calculate the extension of the shock absorber

Answer 1

Elastic Potential Energy = $\frac{1}{2}kx^2$

258$J= \frac{1}{2} \times 4530\times x^2$

$x= \sqrt{\frac{258\times 2}{4530}} = 0.3375 m$