Answer to Question #157086 in Mechanics | Relativity for Femi

Question

A body weighs 0.5kg in air, 0.3kg in water and 0.2kg in a liquid, what is the relative density of the liquid?

Answer 1

Solution:

The relative (to the water's density) density of the liquid is:

$\dfrac{\rho_l}{\rho_w}=\dfrac{F_l}{F_w}=\dfrac{W_a-W_l}{W_a-W_w}=\dfrac{0.5-0.2}{0.5-0.3}=1.5$

The liquid is 1.5 times denser than water and pushes a body up stronger. Less weight remains for the bottom.

Answer:

The relative density of the liquid is 1.5.