Question

a mass of 3kg rests on the smooth table and tied by a light cord passing over a frictionless pulley to 5kg mass hanging freely.what is the acceleration of the system which is released?

Answer 1

A mass of 3kg rests on the smooth table and tied by a light cord passing over a frictionless pulley to 5kg mass hanging freely. What is the acceleration of the system which is released?

Solution:

Let:

$$m1 = 3\,kg$$ $$m2 = 5\,kg$$ $$a - ?$$ $$a = \frac{F}{m1 + m2}$$ $$F = m2 * g, \quad \text{were } g = 9.8\,m/s^2 - \text{acceleration of free fall}$$ $$a = \frac{m2 * g}{m1 + m2} = \frac{5 * 9.8}{3 + 5} = 6.125\,m/s^2$$

Answer: $6.125\,m/s^2$