a boy sitting on a swing at a maximum height of 5m above the ground.when the swing passes through the mean position which is 2m above the ground its velocity is?
1
Expert's answer
2012-10-05T07:55:38-0400
The law of conservation of energy states that the total amount of energy in an isolated system remains constant over time. At a maximum height: K0 = 0 P0 = m * g * H At a lowest point: K1 = m * V^2 / 2 P1 = m * g * h
K0 + P0 = K1 + P1, so: m * g * H = m * V^2 / 2 + m * g * h g * H = V^2 / 2 + g * h V^2 / 2 = g * H - g * h V = sqrt(2 * g * (H - h)) V = sqrt(2 * 9.81 * (5 - 2)) = 7.67 m/s
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