At exactly 2 hr :00min a pendulum Bob is thrown vertically upward from the ground with an initial velocity of 75m/s,at what time will the Bob return to the ground
Answer
time will the Bob return to the ground is given
T=2ug=2×759.8=15.37s\frac{2u}{g}=\frac{2\times75}{9.8}=15.37sg2u=9.82×75=15.37s
So time is 2hr:15min:37sec.
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