Question #155170

A solid sphere is rolling on a rough horizontal surface with linear speed v . It collides with a vertical wall elastically. Coefficient of friction on each surface is 0.5 .Find speed of sphere when it again starts rolling without slipping.


Expert's answer

Ffr=IαF_fr=I\alpha


I=25mr2I=\frac{2}{5}mr^2


α=5Ff2mr\alpha=\frac{5F_f}{2mr}


After collision we have the equation


ωf=−ω+αt→ωf=−ω+5Ff2mrt\omega_f=-\omega+\alpha t\to\omega_f=-\omega+\frac{5F_f}{2mr} t


vf=−v+rαt→vf=−v+5Ff2mtv_f=-v+r\alpha t\to v_f=-v+\frac{5F_f}{2m} t


vf=−v+52(v−vf)→vf=37vv_f=-v+\frac{5}{2}(v-v_f)\to v_f=\frac{3}{7}v . Answer













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