Question

A golf ball rolls up a hill towards a miniature golf hole. Assign the direction toward the hole as being positive a. If the ball starts with a speed of 2.0 m/s and slows at a constant rate of 0.50 m/s squared. What is its velocity after 2.0 seconds?

Answer 1

Question #15378

The speed for an accelerated motion is $v(t) = v_0 + at$ . In our case, the acceleration $a = -0.5\frac{m}{s^2}$ , and $v_0 = 2\frac{m}{s}, t = 2s$ . Hence, the velocity after two seconds is

$$v = 2 \frac {m}{s} - 0. 5 \frac {m}{s ^ {2}}, 2 s = 2 \frac {m}{s} - 1 \frac {m}{s} = 1 \frac {m}{s}.$$