The distance traveled by the car with uniformly accelerated movement is equal to
s=v0t+at2/2s=v_0t+at^2/2s=v0t+at2/2 ,
where v0v_0v0 - initial speed,
a - acceleration.
t - time.
Since initial speed is zero, the acceleration of the car is
a=2s/t2=2⋅110/5.212=8.1 m/s2a=2s/t^2=2\cdot110/5.21^2=8.1\space{m/s^2}a=2s/t2=2⋅110/5.212=8.1 m/s2
Answer: 8.1 m/s28.1\space{m/s^2}8.1 m/s2
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