a ball slowly rolls off a 1 meter high table and falls straight down. how long does it take for the ball to hit the floor and how fast will it be going just before it hits the floor? the accelerations of the ball due to gravity is 9.81 m/sec^2
1
Expert's answer
2012-09-25T11:08:32-0400
We know that
H = gT²/2,
where H is the height of the table, g is the gravity acceleration and t is falling time. So, it will take
T = √(2H/g) = √(2*1[m]/9.81[m/s²]) ≈ 0.45 seconds
for the ball to hit the floor. The velocity of the ball just before it hits the floor will be
V = gT = 9.81[m/s²]*0.45[s] ≈ 4.41 m/s.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment