A father and his son are supposed to carry a load of 500 N. They decided to use a uniform pole that is 4.0 m long and weighs 60 N. The father and his son support the pole at the ends. Where should the load be placed so that the father supports three times as much as his son?
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Expert's answer
2012-09-25T11:24:46-0400
M1=M2=F*l 3F*l=f(4-l) =>4l=4 =>l=1m (from father) Answer: 1 meter from father
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