a)
Work = the Force in line with the motion times the distance.
Fcos60∗7.5=15F4=843.75JFcos60*7.5= \dfrac{15F}{4} =843.75JFcos60∗7.5=415F=843.75J
b)
Force of friction:
Ff=(225∗sin(60)+25∗9.8)∗0.32=140.8NF_f=(225*sin(60)+25*9.8)*0.32=140.8NFf=(225∗sin(60)+25∗9.8)∗0.32=140.8N
Ff is in the opposite direction of motion so that:
Work of friction =−140.8∗7.5=−1056J-140.8*7.5=-1056J−140.8∗7.5=−1056J
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