Answer to Question #150072 in Mechanics | Relativity for shane

Question

A force of 300 N acts on a 2.5 m long and 10 kg rod initially at rest as shown in the picture below. What is the torque acting on the rod?

Answer 1

Answer

300N force is working at one end of the rod so net torque about fixed end

So

$\tau_{net}=mg\frac{L}{2}+FL\\=10\times9.8\times\frac{2.5}{2}+300\times2.5\\\tau_{net}=872.5Nm$