Question

A horizontal force of 10 N is applied to a 4.0 kg block that is at rest on a perfectly smooth, level surface. Find the speed of the block and how far it has gone after 6.0 s?

Answer 1

We have given:

F=10N, m=4.0kg, V_initial=0, and we need to find:

V_final-speed of block, S-reached distance after 6 sec.

We can easily find first acceleration, then speed and distance.

F=$m\times a$=10N -->a=2.5$\frac{m}{s^2}$ ,

Now we find speed of block after 6 seconds:

V_final=V_initial+$a\times t$, V_initial=0 because it was at rest then it moved.

V_final=$2.5\times 6$ =15$\frac{m}{s}$

S=V_initial$\times t$ + $a\times t^2$ =0+90=90 m.

We find asked things.