Question

Chelsea went for a walk. At the beginning of her walk, she was traveling 2.3 m/s. Then she began to jog to reach a maximum speed of 4.2 m/s over a 15 second period. Assume that Chelsea’s acceleration was constant.

Answer 1

Question#14824

Chelsea went for a walk. At the beginning of her walk, she was traveling 2.3 m/s. Then she began to jog to reach a maximum speed of 4.2 m/s over a 15 second period. Assume that Chelsea's acceleration was constant.

Solution:

Let:

$$\begin{array}{l} v1 = 2.3 \, \mathrm{m/s} \\ v2 = 4.2 \, \mathrm{m/s} \\ t = 15 \, \mathrm{s} \\ a - ? \\ \end{array}$$ $$\begin{array}{l} a = \frac{v2 - v1}{t}; \\ a = \frac{4.2 - 2.3}{15} = 0.13 \, \mathrm{m/s^2} \\ \end{array}$$