Answer to Question #148194 in Mechanics | Relativity for Janloe

Question

t^2 + 2(5.0 m/s) /−9.80 m/s^2

Answer 1

I think that given things are not enough to compute but i will simplify it:

$t^2$ + $\frac{2\times(5.0\frac{m}{s})}{-9.80\frac{m}{s^2}}$=$t^2$ - 1.02s. --> this is the thing that we reached maximum simplify.