Question #1474
Metabolizing a candy bar releases about 10^6 joules. How fast must the candy bar travel to have the same 10^6 joules in kinetic energy? The mass of the candy bar is 0.2 kilograms.
Expert's answer
The kinetic energy is
K = mV2/2
Thus
V = √(2*K/m) = √(2*106/0.2) = 2 √(gR) = √(10*39) = 19.75 m/s
K = mV2/2
Thus
V = √(2*K/m) = √(2*106/0.2) = 2 √(gR) = √(10*39) = 19.75 m/s
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#340153 on Dec 2023
#340153 on Dec 2023