Question

The scale on the horizontal axis is 4 s per
division and on the vertical axis 5 m/s per
division. The initial position is 51 m.
1) What is the initial velocity?
Answer in units of m/s
2) What is the position when t = 0?
Answer in units of m
3) What acceleration is represented by the
graph?
Answer in units of m/s^2

THIS IS THE GRAPH:

http://i.imgur.com/7tUsY.jpg

4) What is the position when t = 32 s?
Answer in units of m

Answer 1

Solution

$$\begin{array}{l} 1.V_0 = 6 * 5 \, \mathrm{m/s} = 30 \, \mathrm{m/s} \\ 2.S_{t=0} = 51 \, \mathrm{m} \\ 3.a = \frac{4*5 \, \mathrm{m/s}}{8*4 \, \mathrm{s}} = 0.625 \, \mathrm{m/s^2} \\ 4.S_{t=32} = S_{t=0} + V_0 * t - \frac{a*t^2}{2} = 51 + 30 * 32 - \frac{0.625*32^2}{2} = 691 \, \mathrm{m} \\ \end{array}$$