Question #147271
An alloy of gold and quartz has a mass of 150g.Determine the mass of the gold in the alloy. Relative density of gold is 19.3 of quartz is 2.6 and of the alloy 6.5. Assume that there is no change in volume when the metals form the alloy
1
Expert's answer
2020-11-27T14:08:49-0500

ρ=mV;V=mρ;Valloy=malloyρalloy=1506.523.1\rho = \frac{m}{V};V=\frac{m}{\rho};V_{alloy}=\frac{m_{alloy}}{\rho_{alloy}}=\frac{150}{6.5}\approx23.1

mgold+mquartz=150;mquartz=150mgoldm_{gold}+m_{quartz}=150;m_{quartz}= 150 -m_{gold}

Valloy=Vgold+VquartzV_{alloy} = V_{gold}+V_{quartz}

Vgold+Vquartz=mgoldρgold+mquartzρquqrtz=V_{gold}+V_{quartz} = \frac{m_{gold}}{\rho_{gold}}+\frac{m_{quartz}}{\rho_{quqrtz}}= mgoldρgold+mallowmgoldρquartz\frac{m_{gold}}{\rho_{gold}}+\frac{m_{allow}-m_{gold}}{\rho_{quartz}}

Valloyρgoldρquartz=mgoldρquartz+mallowρgoldmgoldρgoldV_{alloy}*\rho_{gold}*\rho_{quartz} = m_{gold}*\rho_{quartz}+m_{allow}*\rho_{gold}-m_{gold}*\rho_{gold}

mgold=Valloyρgoldρquartzmallowρgoldρquartzρgold103.9m_{gold}= \frac{V_{alloy}*\rho_{gold}*\rho_{quartz} -m_{allow}*\rho_{gold}}{\rho_{quartz}-\rho_{gold}}\approx103.9

Answer:mgold103.9gm_{gold}\approx103.9g


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Comments

king
29.10.23, 10:48

thanks it was very helpful

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