Answer to Question #147092 in Mechanics | Relativity for Mikkos Joshua Garcia

Question

An object with a mass of 34 kg falls from rest from the top of the building. At one instance of its flight, it encounters an air resistance of 312 N. (a) What is its acceleration at this instance? (b) What must be the value of air resistance for the object to attain its terminal velocity?

I need the diagram and complete solution for the given problem above.

Answer 1

Answer

a) by second law of machanics

$F-F_{air}=ma\\a=\frac{(34\times9.8)-312}{34}\\a=0.62m/s^2$

b)

Velocity of object will increase due to gravity and as the velocity increase then air resistance Will also increase.

At terminal velocity air resistance will be equal to the force due to gravity.

And object will fall with constant velocity

So

$W=F_{air}\\F_R=333.2N$