Question

What is the maximum speed with which a 1050 kg car can round a turn of the radius 70 m on a flat road if the coefficient of friction between tires and road is 0.80?

Answer 1

The acceleration due to change in the direction is:
& a = V2/R
Let's write the equation of the force equilibrium
micro; m g = m a
micro; g =& V2/R
V 2= R µ g = 70*0.8 * 10 = 560
The maximum speed would be equal to 23.66 m/s.