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Answer to Question #1465 in Mechanics | Relativity for Mia
Question #1465
The water flow through the turbine of a hydropower plant is
660 m^3/min, and the vertical height from the tail water level to the intake water level is 14 m. The efficiency of the power plant is 86 %, which means that the power plant converts 86 percent of the change in the potential energy of the water into electrical energy. How much power does the hydropower plant deliver to the grid? (g= 9.8 m/s)
660 m^3/min, and the vertical height from the tail water level to the intake water level is 14 m. The efficiency of the power plant is 86 %, which means that the power plant converts 86 percent of the change in the potential energy of the water into electrical energy. How much power does the hydropower plant deliver to the grid? (g= 9.8 m/s)
Expert's answer
Firstly, we should find the water mass fow through the turbine per second:
m/t = 1000[kg/m3]*660 [m3/min]/60[sec] = 11000 [kg/s]
The power of the waterflow would be
W = 0.86mgH/t = 0.86 * 11000 [kg/s] * 9.8 [m/s2] * 14 [m] = 1297912 W = 1.30 MW
m/t = 1000[kg/m3]*660 [m3/min]/60[sec] = 11000 [kg/s]
The power of the waterflow would be
W = 0.86mgH/t = 0.86 * 11000 [kg/s] * 9.8 [m/s2] * 14 [m] = 1297912 W = 1.30 MW
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