Question#14583
There is a 100kg object on a 30-degree incline ramp.
A motor with a string attached to the object accelerates the object at 0.22 m/s^2
The mew of friction is 0.5. What is the power output of the motor?
Solution:
Let:
m=100 kgα=30∘a=0.22 m/s2μ=0.5N−?N=μFv=μFatN=μ(mgcosα+mα)atN=95.78 W
Answer: 95.78 W