Question

there are 2 planes that leaves towards the same city at the same time (15:32pm) one flies at 460km/h and the other flies at 600km/h. how long will it take the faster plane to get 300 km ahead of the slower plane

Answer 1

There are 2 planes that leaves towards the same city at the same time (15:32pm) one flies at 460km/h and the other flies at 600km/h. how long will it take the faster plane to get 300 km ahead of the slower plane.

$$V = \frac {S}{t} \Rightarrow S = V * t$$ $$V _ {1} = 6 0 0 k m / h$$ $$S _ {1} = 6 0 0 * t$$ $$V _ {2} = 4 6 0 k m / h$$ $$S _ {2} = 4 6 0 * t$$ $$S _ {1} - S _ {2} = 3 0 0$$ $$6 0 0 t - 4 6 0 t = 3 0 0$$ $$1 4 0 t = 3 0 0$$ $$t = \frac {3 0 0}{1 4 0} = 2. 1 4 h$$ $$t = 2. 1 4 h = 2 h 8 \min 2 4 \sec$$