A 2.0 kg mass has 300 J energy. What is the speed of the mass
The kinetic energy of the body is
E=mv22=300 J\displaystyle E = \frac{mv^2}{2} = 300 \; JE=2mv2=300J .
The mass is given: m=2.0 kgm=2.0 \; kgm=2.0kg.
So, the speed is
v=2Em=6002=300≈17.3 ms.\displaystyle v = \sqrt{\frac{2E}{m}} = \sqrt{\frac{600}{2}} = \sqrt{300} \approx 17.3 \; \frac{m}{s}.v=m2E=2600=300≈17.3sm.
Answer: 17.3 m/s.
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