2 cars off to raise with velocity 2m/s & 4m/s travel in straight line with uniform acceleration 2m/s*s & 1m/s*s . what is the length covered if reach in same time?
1
Expert's answer
2012-09-07T10:58:04-0400
Let the length covered is L and the time of race is t. For the first car: S1 = V10 * t + a1 * t^2 / 2. For the second car: S2 = V20 * t + a2 * t^2 / 2. S1 = S2 = L, so: 2 * t + 2 * t^2 / 2 = 4 * t + 1 * t^2 / 2 t^2 - 4 * t = 0 t * (t - 4) = 0 t = {0, 4}. At finish line t = 4 s. Calculating L = 2 * 4 + 2 * 4^2 / 2 = 8 + 16 = 24 m.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment