a) F=p△t=321.3=24.6F=\frac{p}{\triangle t}=\frac{32}{ 1.3}=24.6F=△tp=1.332=24.6 N
b) E=mv22=(mv)22m=p22m=3222⋅4=128E=\frac{mv^2}{2}=\frac{(mv)^2}{2m}=\frac{p^2}{2m}=\frac{32^2}{2\cdot4}=128E=2mv2=2m(mv)2=2mp2=2⋅4322=128 J
c) p=32p=32p=32 kg⋅ms\frac{kg\cdot m}{s}skg⋅m
d) v=0v=0v=0 ms\frac{ m}{s}sm, so p=0p=0p=0 kg⋅ms\frac{kg\cdot m}{s}skg⋅m
e) v=0v=0v=0 ms\frac{ m}{s}sm, so E=0E=0E=0 J
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments