Answer to Question #144277 in Mechanics | Relativity for Monzer

Question

A 3 kilogram mass is travelling at 15 meters per second when friction begins to decelerate it to stop in 5 seconds. What is the magnitude of the force of friction?

Answer 1

Answer

Deceleration can be obtain as

$v=u-at\\0=15-a\times5\\a=3m/s^2$

So friction force can be given

$f=ma\\f=3\times3\\f=9N$