Answer
a. Free body diagram can be drawn as
b. There are static coefficient of friction
Will be
"\\mu_s=\\frac{230}{500}=0.46"
Kinetic coefficient of friction will be
"\\mu_k=\\frac{200}{500}=0.40"
Force on the block just before it star to move.
In forward direction F=200N
In backward direction due to friction
f=200N
Vertically upward Normal reaction N=500N
Vertically downward W=mg=500N
Block is moving with constant velociy so there are no any acceleration so appalied force will be equal to kinetic friction.
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