(a) How long does the bomb take to reach the ground?
d = distance fallen by the bomb = 5,000 ft
g = gravitational acceleration = 32.17"( \\tfrac{ft}{sec^2}\t)"
t = elapsed time of bomb's fall = to be determined
"t=\\sqrt{\\tfrac{2d}{g}\t}"
"t=\\sqrt{\\tfrac{2(5,000)}{32.17}\t}"
t = 17.63089949 sec
(b) What will the bomb's velocity be on impact?
v = velocity of bomb on impact = to be determined
"v=\\sqrt{2gd\t}"
"v=\\sqrt{2*32.17*5,000\t}"
v = 567.1860365 "(\\tfrac{ft}{sec})"
Comments
Leave a comment