Let F1=10F_1=10F1=10 N, F2=20F_2=20F2=20 N, α=−30°.\alpha =-30°.α=−30°.
So the net force is F=F1+F2cosα=27.3F=F_1+F_2cos\alpha=27.3F=F1+F2cosα=27.3 N.
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