Given,
Horizontal force FH=600NF_H=600NFH=600N
Let the force in the wire be TTT
Angle made with horizontal θ=60∘\theta=60^{\circ}θ=60∘
then for Equllibrium
∑F=0\sum F=0∑F=0
⇒Tcos60∘=600⇒T×12=600⇒T=1200N\Rightarrow Tcos60^{\circ}=600\\\Rightarrow T\times \dfrac{1}{2}=600\\\Rightarrow T=1200N⇒Tcos60∘=600⇒T×21=600⇒T=1200N
Hence the force in the stay wire is 1200N1200N1200N .
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments