Question #141528

12 passengers per minute on average move on to an elevator (lift) which is rising steadily at 2m/s. Assuming the initial velocity of the passengers is zero, calculate the extra tension (force) due to the passengers on the belt round the elevator rollers. Average passenger mass = 60 kg.

Expert's answer

Answer

Thrust force applied by man on lift can be given as

F=−dmdtvF=-\frac{dm}{dt}v

Mass of average person =60

And 12 persons per minute

So

dmdt=12×60=720kg/minute=12kg/s\frac{dm}{dt}=12\times60=720kg/minute\\=12kg/s

So extra tension force

F=12×2=24NF=12\times2=24N


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