A force of magnitude 200 N is directed West, and a second force of magnitude 100 N is directed East of
North. Find the magnitude and direction of a third force that, when added to the first two forces, gives a
resultant whose magnitude is zero.
1
Expert's answer
2020-10-30T13:17:40-0400
Answer
F1=200NF2=100N
Assuming that F2 is 30° east of North
resulant force in x -direction
Fx=200−100sin30°=150N
Force in vertical direction
Fy=−100cos30°=−86.6N
Resulatant force
FR=Fx2+Fy2
FR=1502+86.62=173.2N
Angle
tanθ=150−86.6θ=−30°
So third force of 173.2N should be applied -30° below horizontal or 60° east of South.
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