Solution
Diagram is shown as
Here is useful component
Is x- axis
Fx=FcosθFx=60cos30°Fx=60×32F_x=F\cos \theta \\F_x=60\cos 30^°\\ F_x=60\times\frac{\sqrt{3}}{2}Fx=FcosθFx=60cos30°Fx=60×23
Fx=51.96lbF_x=51.96lbFx=51.96lb
Change in Newton
Fx=203.77NF_x=203.77NFx=203.77N
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