Answer to Question #139198 in Mechanics | Relativity for Al francis

Question

A stone is thrown with an initial velocity of 55 ft/
s, at an angle of 23° with the horizontal. Find the
vertical and horizontal components of the velocity

Answer 1

$\vert{V_x}\vert=\vert{V*\cos(a)}\vert = 55*\cos(23^0)\approx50.63$ ft/s

$\vert{V_y}\vert=\vert{V*\cos(90-a)}\vert = \vert{V*\sin(a)}\vert =$ $55*\sin(23^0)\approx$ 21.49 ft/s

Answer:

21.49 ft/s vertical component of the velocity

50.63 ft/s horizontal component of the velocity